Physics — Semester B
Free Practice · 10 Questions · 20 min
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Question 1 of 10
TEKS 8E-9DMedium Calc Word

What is the energy of a photon with frequency 5.0 × 10¹⁴ Hz? Use h = 6.63 × 10⁻³⁴ J·s.

Photon with frequency f = 5.0 × 10¹⁴ Hzwave, f = 5.0 × 10¹⁴ HzγphotonE = h·f = ?h = 6.63 × 10⁻³⁴ J·sFind the photon energy.
A3.3 × 10⁻²⁰ J
B5.0 × 10¹⁴ J
C3.3 × 10⁻¹⁹ J
D1.3 × 10¹⁹ J
Explanation
📌 E = hf = (6.63 × 10⁻³⁴)(5.0 × 10¹⁴) = 33.15 × 10⁻²⁰ = 3.3 × 10⁻¹⁹ J. Distractor B: wrong sign of exponent; C: reported f; D: off by factor of 10.
Question 2 of 10
TEKS 6A-6EEasy Word

Which of the following is a good conductor of electricity?

AGlass
BCopper
CWood
DRubber
Explanation
📌 Metals are conductors because their electrons can move freely. Copper is one of the most-used conductors. Wood, rubber, and glass are insulators.
Question 3 of 10
TEKS 8A-8DMedium Calc Word

A wave has a wavelength of 0.5 m and a frequency of 340 Hz. What is its speed?

A680 m/s
B68 m/s
C170 m/s
D0.0015 m/s
Explanation
📌 v = λf = 0.5 × 340 = 170 m/s. Distractor A: divided; C: multiplied wrong; D: reciprocal.
Question 4 of 10
TEKS 6A-6EMedium Calc Word Diagram

In the circuit shown, a 12 V battery drives current through two resistors in series: R₁ = 4 Ω and R₂ = 8 Ω. What is the current through R₁?

12 VR14 ΩR28 ΩI
A0.5 A
B3.0 A
C1.5 A
D1.0 A
Explanation
📌 Series: R_total = 4 + 8 = 12 Ω. Current is the same everywhere: I = V/R = 12/12 = 1.0 A. Distractor A: only used R₂; C: split difference; D: forgot to add resistors (used just R₁: 12/4 = 3).
Question 5 of 10
TEKS 6A-6EMedium Calc Word Diagram

The diagram shows two point charges. Charge A has +4 μC and charge B has +2 μC. They are separated by 0.10 m. What is the direction of the force on charge B due to charge A?

A+4 μCB+2 μC0.10 m
APerpendicular to the line AB
BToward A (attractive)
CAway from A (repulsive)
DZero force
Explanation
📌 Both charges are positive (like charges). Like charges REPEL. So force on B points AWAY from A. Magnitudes are given: F = kq_A q_B/d² = (8.99×10⁹)(4×10⁻⁶)(2×10⁻⁶)/(0.10)² = 7.19 N, but the question asks direction only. Distractor A: opposite direction; C: force is nonzero; D: force is along line, not perpendicular.
Question 6 of 10
TEKS 8A-8DMedium Calc Word

The frequency of a wave is 500 Hz. What is its period?

Wave with frequency 500 Hz — find the periodT = ?f = 500 Hz
A500 s
B500 ms
C2 ms
D0.5 s
Explanation
📌 T = 1/f = 1/500 = 0.002 s = 2 ms. Distractor A: T = f; C: wrong reciprocal; D: 500 ms is 0.5s.
Question 7 of 10
TEKS 6A-6EEasy Word

A 12 V battery is connected across a 4 Ω resistor. What is the current through the resistor?

12 V battery across 4 Ω resistor — current+−V = 12 VR = 4 ΩIFind the current I through the resistor.
A48 A
B16 A
C0.33 A
D3.0 A
Explanation
📌 Ohm's law: I = V/R = 12/4 = 3.0 A. Distractor A: reciprocal (R/V); C: multiplied V × R; D: added V + R.
Question 8 of 10
TEKS 8GHard Calc Word Diagram

The ray diagram shows an object placed farther than 2f from a converging (convex) lens. What is TRUE of the image?

Converging lens · object at distance 3F from the lens2FFF′2F′lensobjectd0 = 3F
AReal, upright, and enlarged
BVirtual, inverted, and same size
CReal, inverted, and reduced
DVirtual, upright, and enlarged
Explanation
📌 Object beyond 2f of a converging lens: image is on the OPPOSITE side (real), inverted (flipped), and reduced (smaller than object). This is how a camera lens works. Distractor B: describes a magnifying glass (object within f); C: converging lens never produces upright real image; D: nonsense combination.
Question 9 of 10
TEKS 6A-6EMedium Calc Word Diagram

The diagram shows electric field lines around two point charges. What is the sign of each charge?

AB
AA is −, B is +
BA is +, B is −
CA is +, B is +
DA is −, B is −
Explanation
📌 Field lines EMERGE from positive charges and CONVERGE into negative charges. In the diagram, arrows point OUT of A (so A is positive) and INTO B (so B is negative). Distractor A: both would show outward arrows; C: reversed; D: both would show inward arrows.
Question 10 of 10
TEKS 8E-9DMedium Calc Word Diagram

The diagram shows energy levels of an atom. An electron transitions from level n = 3 to level n = 1. What happens?

Electron transition n = 3 → n = 1E3E2E1n = 3n = 2n = 1e-
AThe atom emits a photon with energy equal to E₃ − E₁
BNothing happens
CThe atom absorbs a photon of energy hf
DThe atom loses one proton
Explanation
📌 When an electron drops from a higher energy level to a lower one, the atom emits a photon whose energy = E_higher − E_lower. Frequency of the emitted photon is set by hf = ΔE. This is the origin of emission spectra. Distractor A: absorption is the reverse process; C: protons are in the nucleus, not affected by electron transitions; D: emission happens.

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